Base | Representation |
---|---|
bin | 10011000101010110110… |
… | …100011001000100101111 |
3 | 11122101000020002212000010 |
4 | 103011112310121010233 |
5 | 132441242412200142 |
6 | 2442243032104303 |
7 | 163514151451026 |
oct | 23052664310457 |
9 | 4571006085003 |
10 | 1311421600047 |
11 | 466197339379 |
12 | 1921b4535093 |
13 | 96888486b70 |
14 | 4768a4438bd |
15 | 241a69e2e9c |
hex | 13156d1912f |
1311421600047 has 16 divisors (see below), whose sum is σ = 1884368353280. Its totient is φ = 806470916832.
The previous prime is 1311421600043. The next prime is 1311421600061. The reversal of 1311421600047 is 7400061241131.
It is not a de Polignac number, because 1311421600047 - 22 = 1311421600043 is a prime.
It is a super-2 number, since 2×13114216000472 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1311421599987 and 1311421600023.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311421600043) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11562847 + ... + 11675712.
It is an arithmetic number, because the mean of its divisors is an integer number (117773022080).
Almost surely, 21311421600047 is an apocalyptic number.
1311421600047 is a deficient number, since it is larger than the sum of its proper divisors (572946753233).
1311421600047 is a wasteful number, since it uses less digits than its factorization.
1311421600047 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23240022.
The product of its (nonzero) digits is 4032, while the sum is 30.
Adding to 1311421600047 its reverse (7400061241131), we get a palindrome (8711482841178).
The spelling of 1311421600047 in words is "one trillion, three hundred eleven billion, four hundred twenty-one million, six hundred thousand, forty-seven".
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