Base | Representation |
---|---|
bin | 10011000101010110110… |
… | …110000101100100100111 |
3 | 11122101000020221102121200 |
4 | 103011112312011210213 |
5 | 132441243020410310 |
6 | 2442243045413543 |
7 | 163514155311465 |
oct | 23052666054447 |
9 | 4571006842550 |
10 | 1311422044455 |
11 | 466197612256 |
12 | 1921b470a2b3 |
13 | 968885b1223 |
14 | 4768a51b835 |
15 | 241a6a7e9c0 |
hex | 13156d85927 |
1311422044455 has 24 divisors (see below), whose sum is σ = 2273311675440. Its totient is φ = 699369665280.
The previous prime is 1311422044433. The next prime is 1311422044463. The reversal of 1311422044455 is 5544402241131.
1311422044455 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 4 + 2 + 204 + 445 + 5 = 666.
It is not a de Polignac number, because 1311422044455 - 26 = 1311422044391 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 577341 + ... + 1719350.
It is an arithmetic number, because the mean of its divisors is an integer number (94721319810).
Almost surely, 21311422044455 is an apocalyptic number.
1311422044455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1311422044455 is a deficient number, since it is larger than the sum of its proper divisors (961889630985).
1311422044455 is a wasteful number, since it uses less digits than its factorization.
1311422044455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2309391 (or 2309388 counting only the distinct ones).
The product of its (nonzero) digits is 76800, while the sum is 36.
Adding to 1311422044455 its reverse (5544402241131), we get a palindrome (6855824285586).
The spelling of 1311422044455 in words is "one trillion, three hundred eleven billion, four hundred twenty-two million, forty-four thousand, four hundred fifty-five".
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