1311423410535 has 256 divisors, whose sum is σ = 2739938918400. Its totient is φ = 521937561600.

The previous prime is 1311423410533. The next prime is 1311423410551. The reversal of 1311423410535 is 5350143241131.

It is not a de Polignac number, because 1311423410535 - 2¹ = 1311423410533 is a prime.

It is a super-2 number, since 2×1311423410535² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1311423410496 and 1311423410505.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311423410533) by changing a digit.

It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 109397812 + ... + 109409798.

It is an arithmetic number, because the mean of its divisors is an integer number (10702886400).

Almost surely, 2^{1311423410535} is an apocalyptic number.

1311423410535 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

1311423410535 is an abundant number, since it is smaller than the sum of its proper divisors (1428515507865).

1311423410535 is a wasteful number, since it uses less digits than its factorization.

1311423410535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12142.

The product of its (nonzero) digits is 21600, while the sum is 33.

Adding to 1311423410535 its reverse (5350143241131), we get a palindrome (6661566651666).

The spelling of 1311423410535 in words is "one trillion, three hundred eleven billion, four hundred twenty-three million, four hundred ten thousand, five hundred thirty-five".