Base | Representation |
---|---|
bin | 11000011011010101… |
… | …10110110110101111 |
3 | 1020211221202102212120 |
4 | 30031222312312233 |
5 | 203324221143211 |
6 | 10005151404023 |
7 | 642661130055 |
oct | 141552666657 |
9 | 36757672776 |
10 | 13114240431 |
11 | 561a712a36 |
12 | 265bb23613 |
13 | 130cc601a6 |
14 | 8c59c61d5 |
15 | 51b4bad06 |
hex | 30dab6daf |
13114240431 has 4 divisors (see below), whose sum is σ = 17485653912. Its totient is φ = 8742826952.
The previous prime is 13114240429. The next prime is 13114240459. The reversal of 13114240431 is 13404241131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13114240431 - 21 = 13114240429 is a prime.
It is a super-3 number, since 3×131142404313 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13114240411) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2185706736 + ... + 2185706741.
It is an arithmetic number, because the mean of its divisors is an integer number (4371413478).
Almost surely, 213114240431 is an apocalyptic number.
13114240431 is a deficient number, since it is larger than the sum of its proper divisors (4371413481).
13114240431 is an equidigital number, since it uses as much as digits as its factorization.
13114240431 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4371413480.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 13114240431 its reverse (13404241131), we get a palindrome (26518481562).
The spelling of 13114240431 in words is "thirteen billion, one hundred fourteen million, two hundred forty thousand, four hundred thirty-one".
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