Base | Representation |
---|---|
bin | 11101110100010111111000… |
… | …111001010001001110111110 |
3 | 122012100002111012010121121011 |
4 | 131310113320321101032332 |
5 | 114142114130011224014 |
6 | 1142525554212225434 |
7 | 36423504141242362 |
oct | 3564277071211676 |
9 | 565302435117534 |
10 | 131142412211134 |
11 | 388712038aa185 |
12 | 1286034060b27a |
13 | 58238a40b577c |
14 | 24554803512a2 |
15 | 10264ad6ba7c4 |
hex | 7745f8e513be |
131142412211134 has 4 divisors (see below), whose sum is σ = 196713618316704. Its totient is φ = 65571206105566.
The previous prime is 131142412211113. The next prime is 131142412211149. The reversal of 131142412211134 is 431112214241131.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 131142412211096 and 131142412211105.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32785603052782 + ... + 32785603052785.
It is an arithmetic number, because the mean of its divisors is an integer number (49178404579176).
Almost surely, 2131142412211134 is an apocalyptic number.
131142412211134 is a deficient number, since it is larger than the sum of its proper divisors (65571206105570).
131142412211134 is an equidigital number, since it uses as much as digits as its factorization.
131142412211134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65571206105569.
The product of its digits is 4608, while the sum is 31.
Adding to 131142412211134 its reverse (431112214241131), we get a palindrome (562254626452265).
The spelling of 131142412211134 in words is "one hundred thirty-one trillion, one hundred forty-two billion, four hundred twelve million, two hundred eleven thousand, one hundred thirty-four".
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