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131142412211134 = 265571206105567
BaseRepresentation
bin11101110100010111111000…
…111001010001001110111110
3122012100002111012010121121011
4131310113320321101032332
5114142114130011224014
61142525554212225434
736423504141242362
oct3564277071211676
9565302435117534
10131142412211134
11388712038aa185
121286034060b27a
1358238a40b577c
1424554803512a2
1510264ad6ba7c4
hex7745f8e513be

131142412211134 has 4 divisors (see below), whose sum is σ = 196713618316704. Its totient is φ = 65571206105566.

The previous prime is 131142412211113. The next prime is 131142412211149. The reversal of 131142412211134 is 431112214241131.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 131142412211096 and 131142412211105.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32785603052782 + ... + 32785603052785.

It is an arithmetic number, because the mean of its divisors is an integer number (49178404579176).

Almost surely, 2131142412211134 is an apocalyptic number.

131142412211134 is a deficient number, since it is larger than the sum of its proper divisors (65571206105570).

131142412211134 is an equidigital number, since it uses as much as digits as its factorization.

131142412211134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65571206105569.

The product of its digits is 4608, while the sum is 31.

Adding to 131142412211134 its reverse (431112214241131), we get a palindrome (562254626452265).

The spelling of 131142412211134 in words is "one hundred thirty-one trillion, one hundred forty-two billion, four hundred twelve million, two hundred eleven thousand, one hundred thirty-four".

Divisors: 1 2 65571206105567 131142412211134