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131142422220377 is a prime number
BaseRepresentation
bin11101110100010111111001…
…011111011100111001011001
3122012100002111212222010200212
4131310113321133130321121
5114142114140042023002
61142525555210540505
736423504322311011
oct3564277137347131
9565302455863625
10131142422220377
1138871209516287
1212860343a37735
1358238a61ab5b9
1424554817d8c41
1510264ae4e6352
hex7745f97dce59

131142422220377 has 2 divisors, whose sum is σ = 131142422220378. Its totient is φ = 131142422220376.

The previous prime is 131142422220361. The next prime is 131142422220409. The reversal of 131142422220377 is 773022224241131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 120646740212761 + 10495682007616 = 10983931^2 + 3239704^2 .

It is a cyclic number.

It is not a de Polignac number, because 131142422220377 - 24 = 131142422220361 is a prime.

It is a super-2 number, since 2×1311424222203772 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131142422220307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571211110188 + 65571211110189.

It is an arithmetic number, because the mean of its divisors is an integer number (65571211110189).

Almost surely, 2131142422220377 is an apocalyptic number.

It is an amenable number.

131142422220377 is a deficient number, since it is larger than the sum of its proper divisors (1).

131142422220377 is an equidigital number, since it uses as much as digits as its factorization.

131142422220377 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 225792, while the sum is 41.

The spelling of 131142422220377 in words is "one hundred thirty-one trillion, one hundred forty-two billion, four hundred twenty-two million, two hundred twenty thousand, three hundred seventy-seven".