1311430314301 has 4 divisors (see below), whose sum is σ = 1315003694272. Its totient is φ = 1307856934332.

The previous prime is 1311430314283. The next prime is 1311430314331. The reversal of 1311430314301 is 1034130341131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1311430314301 - 2³⁹ = 761674500413 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311430314331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1786689435 + ... + 1786690168.

It is an arithmetic number, because the mean of its divisors is an integer number (328750923568).

Almost surely, 2^{1311430314301} is an apocalyptic number.

It is an amenable number.

1311430314301 is a deficient number, since it is larger than the sum of its proper divisors (3573379971).

1311430314301 is an equidigital number, since it uses as much as digits as its factorization.

1311430314301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3573379970.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1311430314301 its reverse (1034130341131), we get a palindrome (2345560655432).

The spelling of 1311430314301 in words is "one trillion, three hundred eleven billion, four hundred thirty million, three hundred fourteen thousand, three hundred one".