1311432023121 has 64 divisors (see below), whose sum is σ = 2065356057600. Its totient is φ = 731504390400.

The previous prime is 1311432023107. The next prime is 1311432023173. The reversal of 1311432023121 is 1213202341131.

It is not a de Polignac number, because 1311432023121 - 2¹⁵ = 1311431990353 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1311432023091 and 1311432023100.

It is not an unprimeable number, because it can be changed into a prime (1311432023021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 15245251 + ... + 15331031.

It is an arithmetic number, because the mean of its divisors is an integer number (32271188400).

Almost surely, 2^{1311432023121} is an apocalyptic number.

1311432023121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1311432023121 is a deficient number, since it is larger than the sum of its proper divisors (753924034479).

1311432023121 is a wasteful number, since it uses less digits than its factorization.

1311432023121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 86510.

The product of its (nonzero) digits is 864, while the sum is 24.

Adding to 1311432023121 its reverse (1213202341131), we get a palindrome (2524634364252).

The spelling of 1311432023121 in words is "one trillion, three hundred eleven billion, four hundred thirty-two million, twenty-three thousand, one hundred twenty-one".