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1311433162001 is a prime number
BaseRepresentation
bin10011000101010111100…
…000011111110100010001
311122101001000212021000122
4103011113200133310101
5132441303342141001
62442244124000025
7163514351644244
oct23052740376421
94571030767018
101311433162001
114661a2916006
121921b8390015
139688a9a4661
144768bbb325b
15241a7a28b1b
hex1315781fd11

1311433162001 has 2 divisors, whose sum is σ = 1311433162002. Its totient is φ = 1311433162000.

The previous prime is 1311433161979. The next prime is 1311433162031. The reversal of 1311433162001 is 1002613341131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1307878140625 + 3555021376 = 1143625^2 + 59624^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311433162001 - 230 = 1310359420177 is a prime.

It is a super-2 number, since 2×13114331620012 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1311433162031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655716581000 + 655716581001.

It is an arithmetic number, because the mean of its divisors is an integer number (655716581001).

Almost surely, 21311433162001 is an apocalyptic number.

It is an amenable number.

1311433162001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311433162001 is an equidigital number, since it uses as much as digits as its factorization.

1311433162001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 26.

The spelling of 1311433162001 in words is "one trillion, three hundred eleven billion, four hundred thirty-three million, one hundred sixty-two thousand, one".