1311434012432 has 10 divisors (see below), whose sum is σ = 2540903399118. Its totient is φ = 655717006208.

The previous prime is 1311434012429. The next prime is 1311434012437. The reversal of 1311434012432 is 2342104341131.

It can be written as a sum of positive squares in only one way, i.e., 1293050991376 + 18383021056 = 1137124^2 + 135584^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1311434012395 and 1311434012404.

It is not an unprimeable number, because it can be changed into a prime (1311434012437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40982312873 + ... + 40982312904.

Almost surely, 2^{1311434012432} is an apocalyptic number.

It is an amenable number.

1311434012432 is a deficient number, since it is larger than the sum of its proper divisors (1229469386686).

1311434012432 is an equidigital number, since it uses as much as digits as its factorization.

1311434012432 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 81964625785 (or 81964625779 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1311434012432 its reverse (2342104341131), we get a palindrome (3653538353563).

The spelling of 1311434012432 in words is "one trillion, three hundred eleven billion, four hundred thirty-four million, twelve thousand, four hundred thirty-two".