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131143412400 = 2435271113432539
BaseRepresentation
bin111101000100011000…
…0011010101010110000
3110112111121110121120020
41322020300122222300
54122040203144100
6140125122243440
712321566420130
oct1721060325260
9415447417506
10131143412400
1150688045860
12214bb7b6580
13c49ca45310
1464c12a8ac0
1536284225a0
hex1e88c1aab0

131143412400 has 960 divisors, whose sum is σ = 577389711360. Its totient is φ = 24559718400.

The previous prime is 131143412383. The next prime is 131143412423. The reversal of 131143412400 is 4214341131.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 51650331 + ... + 51652869.

It is an arithmetic number, because the mean of its divisors is an integer number (601447616).

Almost surely, 2131143412400 is an apocalyptic number.

131143412400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131143412400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (288694855680).

131143412400 is an abundant number, since it is smaller than the sum of its proper divisors (446246298960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131143412400 is a wasteful number, since it uses less digits than its factorization.

131143412400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2634 (or 2623 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 131143412400 its reverse (4214341131), we get a palindrome (135357753531).

The spelling of 131143412400 in words is "one hundred thirty-one billion, one hundred forty-three million, four hundred twelve thousand, four hundred".