13114342231 has 4 divisors (see below), whose sum is σ = 13130553600. Its totient is φ = 13098130864.

The previous prime is 13114342211. The next prime is 13114342243. The reversal of 13114342231 is 13224341131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13114342231 - 2²⁷ = 12980124503 is a prime.

It is a super-2 number, since 2×13114342231² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13114342196 and 13114342205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13114342211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8104471 + ... + 8106088.

It is an arithmetic number, because the mean of its divisors is an integer number (3282638400).

Almost surely, 2^13114342231 is an apocalyptic number.

13114342231 is a deficient number, since it is larger than the sum of its proper divisors (16211369).

13114342231 is an equidigital number, since it uses as much as digits as its factorization.

13114342231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16211368.

The product of its digits is 1728, while the sum is 25.

Adding to 13114342231 its reverse (13224341131), we get a palindrome (26338683362).

The spelling of 13114342231 in words is "thirteen billion, one hundred fourteen million, three hundred forty-two thousand, two hundred thirty-one".