Base | Representation |
---|---|
bin | 1011111011010110111111… |
… | …1101000010000011001001 |
3 | 1201102201121000112201100212 |
4 | 2332311233331002003021 |
5 | 3204331304314043331 |
6 | 43520402305210505 |
7 | 2522325250562561 |
oct | 276655775020311 |
9 | 51381530481325 |
10 | 13114413424841 |
11 | 41a6878539253 |
12 | 15797b2630a35 |
13 | 7418b76389c1 |
14 | 334a53419da1 |
15 | 17b208e6ad2b |
hex | bed6ff420c9 |
13114413424841 has 2 divisors, whose sum is σ = 13114413424842. Its totient is φ = 13114413424840.
The previous prime is 13114413424837. The next prime is 13114413424867. The reversal of 13114413424841 is 14842431441131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8290921324816 + 4823492100025 = 2879396^2 + 2196245^2 .
It is a cyclic number.
It is not a de Polignac number, because 13114413424841 - 22 = 13114413424837 is a prime.
It is not a weakly prime, because it can be changed into another prime (13114413424891) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557206712420 + 6557206712421.
It is an arithmetic number, because the mean of its divisors is an integer number (6557206712421).
Almost surely, 213114413424841 is an apocalyptic number.
It is an amenable number.
13114413424841 is a deficient number, since it is larger than the sum of its proper divisors (1).
13114413424841 is an equidigital number, since it uses as much as digits as its factorization.
13114413424841 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 147456, while the sum is 41.
Adding to 13114413424841 its reverse (14842431441131), we get a palindrome (27956844865972).
The spelling of 13114413424841 in words is "thirteen trillion, one hundred fourteen billion, four hundred thirteen million, four hundred twenty-four thousand, eight hundred forty-one".
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