Base | Representation |
---|---|
bin | 1011111011010111000110… |
… | …0111100001110001011011 |
3 | 1201102201122222002001120022 |
4 | 2332311301213201301123 |
5 | 3204331333440421133 |
6 | 43520405143421055 |
7 | 2522326040065046 |
oct | 276656147416133 |
9 | 51381588061508 |
10 | 13114441342043 |
11 | 41a6892276918 |
12 | 15797bba5478b |
13 | 7418c0361962 |
14 | 334a57005c5d |
15 | 17b20b632998 |
hex | bed719e1c5b |
13114441342043 has 2 divisors, whose sum is σ = 13114441342044. Its totient is φ = 13114441342042.
The previous prime is 13114441342031. The next prime is 13114441342061. The reversal of 13114441342043 is 34024314441131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13114441342043 - 28 = 13114441341787 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13114441341994 and 13114441342012.
It is not a weakly prime, because it can be changed into another prime (13114441342243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557220671021 + 6557220671022.
It is an arithmetic number, because the mean of its divisors is an integer number (6557220671022).
Almost surely, 213114441342043 is an apocalyptic number.
13114441342043 is a deficient number, since it is larger than the sum of its proper divisors (1).
13114441342043 is an equidigital number, since it uses as much as digits as its factorization.
13114441342043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 13114441342043 its reverse (34024314441131), we get a palindrome (47138755783174).
The spelling of 13114441342043 in words is "thirteen trillion, one hundred fourteen billion, four hundred forty-one million, three hundred forty-two thousand, forty-three".
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