Base | Representation |
---|---|
bin | 1011111011010111000111… |
… | …0010100101100110101011 |
3 | 1201102201200011112100122001 |
4 | 2332311301302211212223 |
5 | 3204331340211210243 |
6 | 43520405325511431 |
7 | 2522326103531545 |
oct | 276656162454653 |
9 | 51381604470561 |
10 | 13114444241323 |
11 | 41a6893977117 |
12 | 1579800a12577 |
13 | 7418c0b384c9 |
14 | 334a5755c695 |
15 | 17b20ba06a4d |
hex | bed71ca59ab |
13114444241323 has 2 divisors, whose sum is σ = 13114444241324. Its totient is φ = 13114444241322.
The previous prime is 13114444241281. The next prime is 13114444241357. The reversal of 13114444241323 is 32314244441131.
It is a strong prime.
It is an emirp because it is prime and its reverse (32314244441131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13114444241323 is a prime.
It is not a weakly prime, because it can be changed into another prime (13114444241023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557222120661 + 6557222120662.
It is an arithmetic number, because the mean of its divisors is an integer number (6557222120662).
Almost surely, 213114444241323 is an apocalyptic number.
13114444241323 is a deficient number, since it is larger than the sum of its proper divisors (1).
13114444241323 is an equidigital number, since it uses as much as digits as its factorization.
13114444241323 is an evil number, because the sum of its binary digits is even.
The product of its digits is 110592, while the sum is 37.
Adding to 13114444241323 its reverse (32314244441131), we get a palindrome (45428688682454).
The spelling of 13114444241323 in words is "thirteen trillion, one hundred fourteen billion, four hundred forty-four million, two hundred forty-one thousand, three hundred twenty-three".
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