13114464331 has 2 divisors, whose sum is σ = 13114464332. Its totient is φ = 13114464330.

The previous prime is 13114464313. The next prime is 13114464401. The reversal of 13114464331 is 13346441131.

Together with previous prime (13114464313) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13114464331 - 2⁵ = 13114464299 is a prime.

It is a super-3 number, since 3×13114464331³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 13114464293 and 13114464302.

It is not a weakly prime, because it can be changed into another prime (13114468331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557232165 + 6557232166.

It is an arithmetic number, because the mean of its divisors is an integer number (6557232166).

Almost surely, 2^13114464331 is an apocalyptic number.

13114464331 is a deficient number, since it is larger than the sum of its proper divisors (1).

13114464331 is an equidigital number, since it uses as much as digits as its factorization.

13114464331 is an evil number, because the sum of its binary digits is even.

The product of its digits is 10368, while the sum is 31.

The spelling of 13114464331 in words is "thirteen billion, one hundred fourteen million, four hundred sixty-four thousand, three hundred thirty-one".