Base | Representation |
---|---|
bin | 10011000101011001000… |
… | …111001000010001101001 |
3 | 11122101002220111010221012 |
4 | 103011121013020101221 |
5 | 132441332234111114 |
6 | 2442250524353305 |
7 | 163515126430613 |
oct | 23053107102151 |
9 | 4571086433835 |
10 | 1311460066409 |
11 | 466207021759 |
12 | 1922053a5835 |
13 | 9689343461c |
14 | 476915b7db3 |
15 | 241aa09063e |
hex | 131591c8469 |
1311460066409 has 2 divisors, whose sum is σ = 1311460066410. Its totient is φ = 1311460066408.
The previous prime is 1311460066393. The next prime is 1311460066429. The reversal of 1311460066409 is 9046600641131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 847430713600 + 464029352809 = 920560^2 + 681197^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311460066409 - 24 = 1311460066393 is a prime.
It is not a weakly prime, because it can be changed into another prime (1311460066429) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655730033204 + 655730033205.
It is an arithmetic number, because the mean of its divisors is an integer number (655730033205).
Almost surely, 21311460066409 is an apocalyptic number.
It is an amenable number.
1311460066409 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311460066409 is an equidigital number, since it uses as much as digits as its factorization.
1311460066409 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 93312, while the sum is 41.
The spelling of 1311460066409 in words is "one trillion, three hundred eleven billion, four hundred sixty million, sixty-six thousand, four hundred nine".
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