Base | Representation |
---|---|
bin | 1111101000100… |
… | …10100000111001 |
3 | 100010210000000011 |
4 | 13310102200321 |
5 | 232033212313 |
6 | 21002541521 |
7 | 3151511125 |
oct | 764224071 |
9 | 303700004 |
10 | 131147833 |
11 | 68036343 |
12 | 37b078a1 |
13 | 2122b08b |
14 | 135bc585 |
15 | b7a893d |
hex | 7d12839 |
131147833 has 2 divisors, whose sum is σ = 131147834. Its totient is φ = 131147832.
The previous prime is 131147801. The next prime is 131147837. The reversal of 131147833 is 338741131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 82664464 + 48483369 = 9092^2 + 6963^2 .
It is a cyclic number.
It is not a de Polignac number, because 131147833 - 25 = 131147801 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131147795 and 131147804.
It is not a weakly prime, because it can be changed into another prime (131147837) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65573916 + 65573917.
It is an arithmetic number, because the mean of its divisors is an integer number (65573917).
Almost surely, 2131147833 is an apocalyptic number.
It is an amenable number.
131147833 is a deficient number, since it is larger than the sum of its proper divisors (1).
131147833 is an equidigital number, since it uses as much as digits as its factorization.
131147833 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6048, while the sum is 31.
The square root of 131147833 is about 11451.9794358879. The cubic root of 131147833 is about 508.0662811092.
Adding to 131147833 its reverse (338741131), we get a palindrome (469888964).
The spelling of 131147833 in words is "one hundred thirty-one million, one hundred forty-seven thousand, eight hundred thirty-three".
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