13114903 has 4 divisors (see below), whose sum is σ = 13362408. Its totient is φ = 12867400.

The previous prime is 13114897. The next prime is 13114919. The reversal of 13114903 is 30941131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13114903 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13114943) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 123673 + ... + 123778.

It is an arithmetic number, because the mean of its divisors is an integer number (3340602).

Almost surely, 2^13114903 is an apocalyptic number.

13114903 is a deficient number, since it is larger than the sum of its proper divisors (247505).

13114903 is an equidigital number, since it uses as much as digits as its factorization.

13114903 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 247504.

The product of its (nonzero) digits is 324, while the sum is 22.

The square root of 13114903 is about 3621.4504000469. The cubic root of 13114903 is about 235.8241951728.

Subtracting from 13114903 its sum of digits (22), we obtain a triangular number (13114881 = T₅₁₂₁).

The spelling of 13114903 in words is "thirteen million, one hundred fourteen thousand, nine hundred three".