Base | Representation |
---|---|
bin | 11000011011011100… |
… | …01101000001001010 |
3 | 1020212000102000011212 |
4 | 30031232031001022 |
5 | 203324432231032 |
6 | 10005222253122 |
7 | 643001442404 |
oct | 141556150112 |
9 | 36760360155 |
10 | 13115117642 |
11 | 5620162000 |
12 | 26602871a2 |
13 | 13101a9553 |
14 | 8c5b73b74 |
15 | 51b5e0bb2 |
hex | 30db8d04a |
13115117642 has 16 divisors (see below), whose sum is σ = 21638470464. Its totient is φ = 5961415900.
The previous prime is 13115117633. The next prime is 13115117647. The reversal of 13115117642 is 24671151131.
It is a junction number, because it is equal to n+sod(n) for n = 13115117599 and 13115117608.
It is not an unprimeable number, because it can be changed into a prime (13115117647) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2460734 + ... + 2466057.
It is an arithmetic number, because the mean of its divisors is an integer number (1352404404).
Almost surely, 213115117642 is an apocalyptic number.
13115117642 is a deficient number, since it is larger than the sum of its proper divisors (8523352822).
13115117642 is an equidigital number, since it uses as much as digits as its factorization.
13115117642 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4926826 (or 4926804 counting only the distinct ones).
The product of its digits is 5040, while the sum is 32.
Adding to 13115117642 its reverse (24671151131), we get a palindrome (37786268773).
The spelling of 13115117642 in words is "thirteen billion, one hundred fifteen million, one hundred seventeen thousand, six hundred forty-two".
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