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131152221200 = 245271113327553
BaseRepresentation
bin111101000100101001…
…0000001010000010000
3110112112020001010222002
41322021102001100100
54122044432034300
6140130035133132
712322034325560
oct1721122012020
9415466033862
10131152221200
1150692011a60
12215027441a8
13c4a180a920
1464c251cda0
1536290b25d5
hex1e89481410

131152221200 has 240 divisors, whose sum is σ = 423063505536. Its totient is φ = 37733990400.

The previous prime is 131152221191. The next prime is 131152221241. The reversal of 131152221200 is 2122251131.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 236624 + ... + 564176.

Almost surely, 2131152221200 is an apocalyptic number.

131152221200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131152221200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (211531752768).

131152221200 is an abundant number, since it is smaller than the sum of its proper divisors (291911284336).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131152221200 is a wasteful number, since it uses less digits than its factorization.

131152221200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 327602 (or 327591 counting only the distinct ones).

The product of its (nonzero) digits is 240, while the sum is 20.

Adding to 131152221200 its reverse (2122251131), we get a palindrome (133274472331).

The spelling of 131152221200 in words is "one hundred thirty-one billion, one hundred fifty-two million, two hundred twenty-one thousand, two hundred".