Base | Representation |
---|---|
bin | 10011000101011100110… |
… | …111011010010110110111 |
3 | 11122101021022000022002010 |
4 | 103011130313122112313 |
5 | 132441444400230111 |
6 | 2442301054415303 |
7 | 163516523013120 |
oct | 23053467322667 |
9 | 4571238008063 |
10 | 1311523055031 |
11 | 466239633a72 |
12 | 192222501533 |
13 | 968a34b99b7 |
14 | 47699ad3047 |
15 | 241b0883aa6 |
hex | 1315cdda5b7 |
1311523055031 has 16 divisors (see below), whose sum is σ = 2025888191744. Its totient is φ = 739175419584.
The previous prime is 1311523055027. The next prime is 1311523055069. The reversal of 1311523055031 is 1305503251131.
It is not a de Polignac number, because 1311523055031 - 22 = 1311523055027 is a prime.
It is a super-2 number, since 2×13115230550312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1311523055031.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311523055071) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 427762021 + ... + 427765086.
It is an arithmetic number, because the mean of its divisors is an integer number (126618011984).
Almost surely, 21311523055031 is an apocalyptic number.
1311523055031 is a deficient number, since it is larger than the sum of its proper divisors (714365136713).
1311523055031 is an equidigital number, since it uses as much as digits as its factorization.
1311523055031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 855527190.
The product of its (nonzero) digits is 6750, while the sum is 30.
The spelling of 1311523055031 in words is "one trillion, three hundred eleven billion, five hundred twenty-three million, fifty-five thousand, thirty-one".
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