1311531134433 has 24 divisors (see below), whose sum is σ = 1929299383872. Its totient is φ = 791867838528.

The previous prime is 1311531134413. The next prime is 1311531134447. The reversal of 1311531134433 is 3344311351131.

It is a de Polignac number, because none of the positive numbers 2^k-1311531134433 is a prime.

It is a super-2 number, since 2×1311531134433² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1311531134394 and 1311531134403.

It is not an unprimeable number, because it can be changed into a prime (1311531134413) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 24377341 + ... + 24431082.

It is an arithmetic number, because the mean of its divisors is an integer number (80387474328).

Almost surely, 2^{1311531134433} is an apocalyptic number.

1311531134433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1311531134433 is a deficient number, since it is larger than the sum of its proper divisors (617768249439).

1311531134433 is a wasteful number, since it uses less digits than its factorization.

1311531134433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48808505 (or 48808492 counting only the distinct ones).

The product of its digits is 19440, while the sum is 33.

Adding to 1311531134433 its reverse (3344311351131), we get a palindrome (4655842485564).

The spelling of 1311531134433 in words is "one trillion, three hundred eleven billion, five hundred thirty-one million, one hundred thirty-four thousand, four hundred thirty-three".