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1311531138818 = 2655765569409
BaseRepresentation
bin10011000101011101010…
…110001111111100000010
311122101021212012222221122
4103011131112033330002
5132442003432420233
62442301543552242
7163516651512035
oct23053526177402
94571255188848
101311531138818
1146624315548a
1219222515b682
13968a508a2c4
144769abd901c
15241b142dd98
hex1315d58ff02

1311531138818 has 4 divisors (see below), whose sum is σ = 1967296708230. Its totient is φ = 655765569408.

The previous prime is 1311531138817. The next prime is 1311531138913. The reversal of 1311531138818 is 8188311351131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 910369781689 + 401161357129 = 954133^2 + 633373^2 .

It is a super-2 number, since 2×13115311388182 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1311531138817) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 327882784703 + ... + 327882784706.

Almost surely, 21311531138818 is an apocalyptic number.

1311531138818 is a deficient number, since it is larger than the sum of its proper divisors (655765569412).

1311531138818 is an equidigital number, since it uses as much as digits as its factorization.

1311531138818 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 655765569411.

The product of its digits is 69120, while the sum is 44.

Adding to 1311531138818 its reverse (8188311351131), we get a palindrome (9499842489949).

The spelling of 1311531138818 in words is "one trillion, three hundred eleven billion, five hundred thirty-one million, one hundred thirty-eight thousand, eight hundred eighteen".

Divisors: 1 2 655765569409 1311531138818