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1311531138913 is a prime number
BaseRepresentation
bin10011000101011101010…
…110001111111101100001
311122101021212020000002011
4103011131112033331201
5132442003432421123
62442301543552521
7163516651512232
oct23053526177541
94571255200064
101311531138913
11466243155566
1219222515b741
13968a508a368
144769abd9089
15241b142de0d
hex1315d58ff61

1311531138913 has 2 divisors, whose sum is σ = 1311531138914. Its totient is φ = 1311531138912.

The previous prime is 1311531138817. The next prime is 1311531138917. The reversal of 1311531138913 is 3198311351131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1293717431889 + 17813707024 = 1137417^2 + 133468^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1311531138913 is a prime.

It is a super-2 number, since 2×13115311389132 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1311531138917) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655765569456 + 655765569457.

It is an arithmetic number, because the mean of its divisors is an integer number (655765569457).

Almost surely, 21311531138913 is an apocalyptic number.

It is an amenable number.

1311531138913 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311531138913 is an equidigital number, since it uses as much as digits as its factorization.

1311531138913 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 29160, while the sum is 40.

The spelling of 1311531138913 in words is "one trillion, three hundred eleven billion, five hundred thirty-one million, one hundred thirty-eight thousand, nine hundred thirteen".