131154414132341 has 4 divisors (see below), whose sum is σ = 131154558965184. Its totient is φ = 131154269299500.

The previous prime is 131154414132307. The next prime is 131154414132361. The reversal of 131154414132341 is 143231414451131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131154414132341 - 2¹⁴ = 131154414115957 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131154414132295 and 131154414132304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131154414132361) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71049485 + ... + 72872066.

It is an arithmetic number, because the mean of its divisors is an integer number (32788639741296).

Almost surely, 2^{131154414132341} is an apocalyptic number.

It is an amenable number.

131154414132341 is a deficient number, since it is larger than the sum of its proper divisors (144832843).

131154414132341 is an equidigital number, since it uses as much as digits as its factorization.

131154414132341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 144832842.

The product of its digits is 69120, while the sum is 38.

Adding to 131154414132341 its reverse (143231414451131), we get a palindrome (274385828583472).

The spelling of 131154414132341 in words is "one hundred thirty-one trillion, one hundred fifty-four billion, four hundred fourteen million, one hundred thirty-two thousand, three hundred forty-one".