Base | Representation |
---|---|
bin | 10011000101011110001… |
… | …000011101011001011001 |
3 | 11122101022202222201021020 |
4 | 103011132020131121121 |
5 | 132442020320114040 |
6 | 2442303134033053 |
7 | 163520201422131 |
oct | 23053610353131 |
9 | 4571282881236 |
10 | 1311544301145 |
11 | 46624a625541 |
12 | 192229648789 |
13 | 968a7a18370 |
14 | 4769c863ac1 |
15 | 241b267dcd0 |
hex | 1315e21d659 |
1311544301145 has 32 divisors (see below), whose sum is σ = 2271363316992. Its totient is φ = 642405748992.
The previous prime is 1311544301129. The next prime is 1311544301183. The reversal of 1311544301145 is 5411034451131.
It is not a de Polignac number, because 1311544301145 - 24 = 1311544301129 is a prime.
It is a super-2 number, since 2×13115443011452 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 17032317 + ... + 17109146.
It is an arithmetic number, because the mean of its divisors is an integer number (70980103656).
Almost surely, 21311544301145 is an apocalyptic number.
1311544301145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1311544301145 is a deficient number, since it is larger than the sum of its proper divisors (959819015847).
1311544301145 is a wasteful number, since it uses less digits than its factorization.
1311544301145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34141681.
The product of its (nonzero) digits is 14400, while the sum is 33.
Adding to 1311544301145 its reverse (5411034451131), we get a palindrome (6722578752276).
The spelling of 1311544301145 in words is "one trillion, three hundred eleven billion, five hundred forty-four million, three hundred one thousand, one hundred forty-five".
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