Base | Representation |
---|---|
bin | 111101000100101111… |
… | …0010000110000000111 |
3 | 110112112110002012011121 |
4 | 1322021132100300013 |
5 | 4122101242233112 |
6 | 140130232014411 |
7 | 12322103523061 |
oct | 1721136206007 |
9 | 415473065147 |
10 | 131155430407 |
11 | 506939040a1 |
12 | 21503831407 |
13 | c4a2392571 |
14 | 64c2b16731 |
15 | 36294e8407 |
hex | 1e89790c07 |
131155430407 has 4 divisors (see below), whose sum is σ = 131363284336. Its totient is φ = 130947576480.
The previous prime is 131155430387. The next prime is 131155430477. The reversal of 131155430407 is 704034551131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131155430407 - 223 = 131147041799 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131155430477) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 103926018 + ... + 103927279.
It is an arithmetic number, because the mean of its divisors is an integer number (32840821084).
Almost surely, 2131155430407 is an apocalyptic number.
131155430407 is a deficient number, since it is larger than the sum of its proper divisors (207853929).
131155430407 is an equidigital number, since it uses as much as digits as its factorization.
131155430407 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 207853928.
The product of its (nonzero) digits is 25200, while the sum is 34.
Adding to 131155430407 its reverse (704034551131), we get a palindrome (835189981538).
The spelling of 131155430407 in words is "one hundred thirty-one billion, one hundred fifty-five million, four hundred thirty thousand, four hundred seven".
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