Base | Representation |
---|---|
bin | 111101000100101111… |
… | …0010000110000101001 |
3 | 110112112110002012012212 |
4 | 1322021132100300221 |
5 | 4122101242233231 |
6 | 140130232014505 |
7 | 12322103523140 |
oct | 1721136206051 |
9 | 415473065185 |
10 | 131155430441 |
11 | 50693904122 |
12 | 21503831435 |
13 | c4a2392599 |
14 | 64c2b16757 |
15 | 36294e842b |
hex | 1e89790c29 |
131155430441 has 16 divisors (see below), whose sum is σ = 150125808000. Its totient is φ = 112243667328.
The previous prime is 131155430387. The next prime is 131155430477. The reversal of 131155430441 is 144034551131.
It is a cyclic number.
It is not a de Polignac number, because 131155430441 - 222 = 131151236137 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131155430398 and 131155430407.
It is not an unprimeable number, because it can be changed into a prime (131155430041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14894546 + ... + 14903348.
It is an arithmetic number, because the mean of its divisors is an integer number (9382863000).
Almost surely, 2131155430441 is an apocalyptic number.
It is an amenable number.
131155430441 is a deficient number, since it is larger than the sum of its proper divisors (18970377559).
131155430441 is a wasteful number, since it uses less digits than its factorization.
131155430441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11888.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 131155430441 its reverse (144034551131), we get a palindrome (275189981572).
The spelling of 131155430441 in words is "one hundred thirty-one billion, one hundred fifty-five million, four hundred thirty thousand, four hundred forty-one".
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