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131155434341 = 990713238663
BaseRepresentation
bin111101000100101111…
…0010001101101100101
3110112112110002101120022
41322021132101231211
54122101242344331
6140130232044525
712322103540411
oct1721136215545
9415473071508
10131155434341
1150693907048
1221503833745
13c4a23942a9
1464c2b17d41
1536294e967b
hex1e89791b65

131155434341 has 4 divisors (see below), whose sum is σ = 131168682912. Its totient is φ = 131142185772.

The previous prime is 131155434337. The next prime is 131155434349. The reversal of 131155434341 is 143434551131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 143434551131 = 579232476297.

It is a cyclic number.

It is not a de Polignac number, because 131155434341 - 22 = 131155434337 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131155434349) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6609425 + ... + 6629238.

It is an arithmetic number, because the mean of its divisors is an integer number (32792170728).

Almost surely, 2131155434341 is an apocalyptic number.

It is an amenable number.

131155434341 is a deficient number, since it is larger than the sum of its proper divisors (13248571).

131155434341 is an equidigital number, since it uses as much as digits as its factorization.

131155434341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13248570.

The product of its digits is 43200, while the sum is 35.

Adding to 131155434341 its reverse (143434551131), we get a palindrome (274589985472).

The spelling of 131155434341 in words is "one hundred thirty-one billion, one hundred fifty-five million, four hundred thirty-four thousand, three hundred forty-one".

Divisors: 1 9907 13238663 131155434341