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131158427763409 is a prime number
BaseRepresentation
bin11101110100100110110011…
…011111110000001011010001
3122012101121211100012222002221
4131310212303133300023101
5114142344430001412114
61142541203325141041
736424612052215534
oct3564466337601321
9565347740188087
10131158427763409
1138877a821a76a2
12128634700ba781
135825257155817
14245615d3b0a1b
151026ae9734524
hex7749b37f02d1

131158427763409 has 2 divisors, whose sum is σ = 131158427763410. Its totient is φ = 131158427763408.

The previous prime is 131158427763353. The next prime is 131158427763439. The reversal of 131158427763409 is 904367724851131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 77747953550400 + 53410474213009 = 8817480^2 + 7308247^2 .

It is a cyclic number.

It is not a de Polignac number, because 131158427763409 - 27 = 131158427763281 is a prime.

It is not a weakly prime, because it can be changed into another prime (131158427763439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65579213881704 + 65579213881705.

It is an arithmetic number, because the mean of its divisors is an integer number (65579213881705).

It is a 1-persistent number, because it is pandigital, but 2⋅131158427763409 = 262316855526818 is not.

Almost surely, 2131158427763409 is an apocalyptic number.

It is an amenable number.

131158427763409 is a deficient number, since it is larger than the sum of its proper divisors (1).

131158427763409 is an equidigital number, since it uses as much as digits as its factorization.

131158427763409 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30481920, while the sum is 61.

The spelling of 131158427763409 in words is "one hundred thirty-one trillion, one hundred fifty-eight billion, four hundred twenty-seven million, seven hundred sixty-three thousand, four hundred nine".