Base | Representation |
---|---|
bin | 10011000101100011010… |
… | …000111001101001100111 |
3 | 11122101112202222222211112 |
4 | 103011203100321221213 |
5 | 132442204340300403 |
6 | 2442315451255235 |
7 | 163522265306402 |
oct | 23054320715147 |
9 | 4571482888745 |
10 | 1311630400103 |
11 | 466294191a01 |
12 | 19225244a51b |
13 | 968bc8027aa |
14 | 476aa076d39 |
15 | 241b9ed99d8 |
hex | 13163439a67 |
1311630400103 has 8 divisors (see below), whose sum is σ = 1329240422400. Its totient is φ = 1294045555608.
The previous prime is 1311630400099. The next prime is 1311630400117. The reversal of 1311630400103 is 3010040361131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1311630400103 - 22 = 1311630400099 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311630400303) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6189551 + ... + 6397952.
It is an arithmetic number, because the mean of its divisors is an integer number (166155052800).
Almost surely, 21311630400103 is an apocalyptic number.
1311630400103 is a deficient number, since it is larger than the sum of its proper divisors (17610022297).
1311630400103 is a wasteful number, since it uses less digits than its factorization.
1311630400103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12588901.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 1311630400103 its reverse (3010040361131), we get a palindrome (4321670761234).
The spelling of 1311630400103 in words is "one trillion, three hundred eleven billion, six hundred thirty million, four hundred thousand, one hundred three".
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