1311630400117 has 2 divisors, whose sum is σ = 1311630400118. Its totient is φ = 1311630400116.

The previous prime is 1311630400099. The next prime is 1311630400141. The reversal of 1311630400117 is 7110040361131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1095938890641 + 215691509476 = 1046871^2 + 464426^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1311630400117 is a prime.

It is a super-2 number, since 2×1311630400117² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311630400187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655815200058 + 655815200059.

It is an arithmetic number, because the mean of its divisors is an integer number (655815200059).

Almost surely, 2^{1311630400117} is an apocalyptic number.

It is an amenable number.

1311630400117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311630400117 is an equidigital number, since it uses as much as digits as its factorization.

1311630400117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1512, while the sum is 28.

Adding to 1311630400117 its reverse (7110040361131), we get a palindrome (8421670761248).

The spelling of 1311630400117 in words is "one trillion, three hundred eleven billion, six hundred thirty million, four hundred thousand, one hundred seventeen".