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1311640233451 = 2357027836237
BaseRepresentation
bin10011000101100011110…
…110011010010111101011
311122101120110111120122121
4103011203312122113223
5132442214344432301
62442320442132111
7163522445013142
oct23054366322753
94571513446577
101311640233451
11466299798939
121922557b1037
13968c1866542
14476ab4b6759
15241baccd3a1
hex13163d9a5eb

1311640233451 has 4 divisors (see below), whose sum is σ = 1368668069712. Its totient is φ = 1254612397192.

The previous prime is 1311640233427. The next prime is 1311640233499. The reversal of 1311640233451 is 1543320461131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311640233451 - 25 = 1311640233419 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311640233251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28513918096 + ... + 28513918141.

It is an arithmetic number, because the mean of its divisors is an integer number (342167017428).

Almost surely, 21311640233451 is an apocalyptic number.

1311640233451 is a deficient number, since it is larger than the sum of its proper divisors (57027836261).

1311640233451 is an equidigital number, since it uses as much as digits as its factorization.

1311640233451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 57027836260.

The product of its (nonzero) digits is 25920, while the sum is 34.

Adding to 1311640233451 its reverse (1543320461131), we get a palindrome (2854960694582).

The spelling of 1311640233451 in words is "one trillion, three hundred eleven billion, six hundred forty million, two hundred thirty-three thousand, four hundred fifty-one".

Divisors: 1 23 57027836237 1311640233451