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1543320461131 = 40571221131153
BaseRepresentation
bin10110011101010101000…
…100010101111101001011
312110112120122201120120221
4112131111010111331023
5200241210014224011
63140554105330511
7216333630321031
oct26352504257513
95415518646527
101543320461131
11545578190a89
1220b132a96a37
13b26c4393467
14549a8c1c551
152a22a626971
hex16755115f4b

1543320461131 has 8 divisors (see below), whose sum is σ = 1543876845584. Its totient is φ = 1542764171520.

The previous prime is 1543320461119. The next prime is 1543320461141. The reversal of 1543320461131 is 1311640233451.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1543320461131 - 27 = 1543320461003 is a prime.

It is a super-2 number, since 2×15433204611312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1543320461141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 49524451 + ... + 49555603.

It is an arithmetic number, because the mean of its divisors is an integer number (192984605698).

Almost surely, 21543320461131 is an apocalyptic number.

1543320461131 is a deficient number, since it is larger than the sum of its proper divisors (556384453).

1543320461131 is a wasteful number, since it uses less digits than its factorization.

1543320461131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47421.

The product of its (nonzero) digits is 25920, while the sum is 34.

Adding to 1543320461131 its reverse (1311640233451), we get a palindrome (2854960694582).

The spelling of 1543320461131 in words is "one trillion, five hundred forty-three billion, three hundred twenty million, four hundred sixty-one thousand, one hundred thirty-one".

Divisors: 1 4057 12211 31153 49540027 126387721 380409283 1543320461131