Base | Representation |
---|---|
bin | 11101110100101101011110… |
… | …011110010010110000001011 |
3 | 122012102022022120120220001102 |
4 | 131310231132132102300023 |
5 | 114143004112330030404 |
6 | 1142544350223412015 |
7 | 36425254424654054 |
oct | 3564553636226013 |
9 | 565368276526042 |
10 | 131165591251979 |
11 | 38880018866689 |
12 | 1286492b15400b |
13 | 5825b292a105b |
14 | 245663c92772b |
15 | 1026db859471e |
hex | 774b5e792c0b |
131165591251979 has 2 divisors, whose sum is σ = 131165591251980. Its totient is φ = 131165591251978.
The previous prime is 131165591251829. The next prime is 131165591251997. The reversal of 131165591251979 is 979152195561131.
Together with next prime (131165591251997) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131165591251979 is a prime.
It is not a weakly prime, because it can be changed into another prime (131165591251999) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65582795625989 + 65582795625990.
It is an arithmetic number, because the mean of its divisors is an integer number (65582795625990).
Almost surely, 2131165591251979 is an apocalyptic number.
131165591251979 is a deficient number, since it is larger than the sum of its proper divisors (1).
131165591251979 is an equidigital number, since it uses as much as digits as its factorization.
131165591251979 is an evil number, because the sum of its binary digits is even.
The product of its digits is 22963500, while the sum is 65.
The spelling of 131165591251979 in words is "one hundred thirty-one trillion, one hundred sixty-five billion, five hundred ninety-one million, two hundred fifty-one thousand, nine hundred seventy-nine".
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