Base | Representation |
---|---|
bin | 10011000101100111110… |
… | …111011111010100001001 |
3 | 11122101202011022102002021 |
4 | 103011213313133110021 |
5 | 132442334122442323 |
6 | 2442331250404441 |
7 | 163524223563133 |
oct | 23054767372411 |
9 | 4571664272067 |
10 | 1311707624713 |
11 | 4663238379a2 |
12 | 192274290721 |
13 | 96902800825 |
14 | 476b641a053 |
15 | 241c1b9105d |
hex | 13167ddf509 |
1311707624713 has 2 divisors, whose sum is σ = 1311707624714. Its totient is φ = 1311707624712.
The previous prime is 1311707624671. The next prime is 1311707624719. The reversal of 1311707624713 is 3174267071131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1291830008569 + 19877616144 = 1136587^2 + 140988^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311707624713 - 213 = 1311707616521 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1311707624713.
It is not a weakly prime, because it can be changed into another prime (1311707624719) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655853812356 + 655853812357.
It is an arithmetic number, because the mean of its divisors is an integer number (655853812357).
Almost surely, 21311707624713 is an apocalyptic number.
It is an amenable number.
1311707624713 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311707624713 is an equidigital number, since it uses as much as digits as its factorization.
1311707624713 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 148176, while the sum is 43.
The spelling of 1311707624713 in words is "one trillion, three hundred eleven billion, seven hundred seven million, six hundred twenty-four thousand, seven hundred thirteen".
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