Base | Representation |
---|---|
bin | 111101000101001101… |
… | …1001101011100101111 |
3 | 110112120120010220211211 |
4 | 1322022123031130233 |
5 | 4122114340021123 |
6 | 140132002255251 |
7 | 12322356366022 |
oct | 1721233153457 |
9 | 415516126754 |
10 | 131171407663 |
11 | 506a192703a |
12 | 21509057527 |
13 | c4a579796a |
14 | 64c4cb51b9 |
15 | 362ab0240d |
hex | 1e8a6cd72f |
131171407663 has 4 divisors (see below), whose sum is σ = 136874512368. Its totient is φ = 125468302960.
The previous prime is 131171407657. The next prime is 131171407667. The reversal of 131171407663 is 366704171131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131171407663 - 229 = 130634536751 is a prime.
It is a Smith number, since the sum of its digits (40) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131171407667) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2851552318 + ... + 2851552363.
It is an arithmetic number, because the mean of its divisors is an integer number (34218628092).
Almost surely, 2131171407663 is an apocalyptic number.
131171407663 is a deficient number, since it is larger than the sum of its proper divisors (5703104705).
131171407663 is an equidigital number, since it uses as much as digits as its factorization.
131171407663 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5703104704.
The product of its (nonzero) digits is 63504, while the sum is 40.
Adding to 131171407663 its reverse (366704171131), we get a palindrome (497875578794).
The spelling of 131171407663 in words is "one hundred thirty-one billion, one hundred seventy-one million, four hundred seven thousand, six hundred sixty-three".
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