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1311732931603 is a prime number
BaseRepresentation
bin10011000101101001011…
…000000001110000010011
311122101210220221010121111
4103011221120001300103
5132442412112302403
62442333553034151
7163524651644143
oct23055130016023
94571726833544
101311732931603
11466337052386
12192280855957
1396907b21613
14476b9926923
15241c3ede56d
hex13169601c13

1311732931603 has 2 divisors, whose sum is σ = 1311732931604. Its totient is φ = 1311732931602.

The previous prime is 1311732931589. The next prime is 1311732931657. The reversal of 1311732931603 is 3061392371131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1311732931603 is a prime.

It is a super-2 number, since 2×13117329316032 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1311732931693) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655866465801 + 655866465802.

It is an arithmetic number, because the mean of its divisors is an integer number (655866465802).

Almost surely, 21311732931603 is an apocalyptic number.

1311732931603 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311732931603 is an equidigital number, since it uses as much as digits as its factorization.

1311732931603 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 61236, while the sum is 40.

The spelling of 1311732931603 in words is "one trillion, three hundred eleven billion, seven hundred thirty-two million, nine hundred thirty-one thousand, six hundred three".