1311797083 has 2 divisors, whose sum is σ = 1311797084. Its totient is φ = 1311797082.

The previous prime is 1311797063. The next prime is 1311797089. The reversal of 1311797083 is 3807971131.

It is a strong prime.

It is an emirp because it is prime and its reverse (3807971131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1311797083 - 2⁵ = 1311797051 is a prime.

It is not a weakly prime, because it can be changed into another prime (1311797089) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655898541 + 655898542.

It is an arithmetic number, because the mean of its divisors is an integer number (655898542).

Almost surely, 2^1311797083 is an apocalyptic number.

1311797083 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311797083 is an equidigital number, since it uses as much as digits as its factorization.

1311797083 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31752, while the sum is 40.

The square root of 1311797083 is about 36218.7393899898. The cubic root of 1311797083 is about 1094.6842936591.

The spelling of 1311797083 in words is "one billion, three hundred eleven million, seven hundred ninety-seven thousand, eighty-three".