Base | Representation |
---|---|
bin | 111101000101100010… |
… | …1110111110010011001 |
3 | 110112121100012002200021 |
4 | 1322023011313302121 |
5 | 4122130220404004 |
6 | 140133042110441 |
7 | 12322553424622 |
oct | 1721305676231 |
9 | 415540162607 |
10 | 131182591129 |
11 | 506a8175377 |
12 | 2151094b421 |
13 | c4a7bb20b5 |
14 | 64c6586a49 |
15 | 362bab0d54 |
hex | 1e8b177c99 |
131182591129 has 2 divisors, whose sum is σ = 131182591130. Its totient is φ = 131182591128.
The previous prime is 131182591121. The next prime is 131182591247. The reversal of 131182591129 is 921195281131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 88848705625 + 42333885504 = 298075^2 + 205752^2 .
It is an emirp because it is prime and its reverse (921195281131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131182591129 - 23 = 131182591121 is a prime.
It is not a weakly prime, because it can be changed into another prime (131182591121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65591295564 + 65591295565.
It is an arithmetic number, because the mean of its divisors is an integer number (65591295565).
Almost surely, 2131182591129 is an apocalyptic number.
It is an amenable number.
131182591129 is a deficient number, since it is larger than the sum of its proper divisors (1).
131182591129 is an equidigital number, since it uses as much as digits as its factorization.
131182591129 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 38880, while the sum is 43.
The spelling of 131182591129 in words is "one hundred thirty-one billion, one hundred eighty-two million, five hundred ninety-one thousand, one hundred twenty-nine".
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