1311840953123 has 2 divisors, whose sum is σ = 1311840953124. Its totient is φ = 1311840953122.

The previous prime is 1311840953047. The next prime is 1311840953179. The reversal of 1311840953123 is 3213590481131.

It is a strong prime.

It is an emirp because it is prime and its reverse (3213590481131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1311840953123 - 2¹⁰ = 1311840952099 is a prime.

It is a super-2 number, since 2×1311840953123² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1311840959123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655920476561 + 655920476562.

It is an arithmetic number, because the mean of its divisors is an integer number (655920476562).

Almost surely, 2^{1311840953123} is an apocalyptic number.

1311840953123 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311840953123 is an equidigital number, since it uses as much as digits as its factorization.

1311840953123 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 77760, while the sum is 41.

The spelling of 1311840953123 in words is "one trillion, three hundred eleven billion, eight hundred forty million, nine hundred fifty-three thousand, one hundred twenty-three".