Base | Representation |
---|---|
bin | 1011111011100101111011… |
… | …0110111001110110111111 |
3 | 1201110002221100120202001201 |
4 | 2332321132312321312333 |
5 | 3204413011410314210 |
6 | 43522304125520331 |
7 | 2522526500354101 |
oct | 276713666716677 |
9 | 51402840522051 |
10 | 13118421573055 |
11 | 41a8544a88337 |
12 | 157a530a130a7 |
13 | 7420a5b51136 |
14 | 334d13891571 |
15 | 17b390ca053a |
hex | bee5edb9dbf |
13118421573055 has 8 divisors (see below), whose sum is σ = 15742505842272. Its totient is φ = 10494470622048.
The previous prime is 13118421573017. The next prime is 13118421573077. The reversal of 13118421573055 is 55037512481131.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13118421573055 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13118421572996 and 13118421573014.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 33112944 + ... + 33506773.
It is an arithmetic number, because the mean of its divisors is an integer number (1967813230284).
Almost surely, 213118421573055 is an apocalyptic number.
13118421573055 is a deficient number, since it is larger than the sum of its proper divisors (2624084269217).
13118421573055 is an equidigital number, since it uses as much as digits as its factorization.
13118421573055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66659105.
The product of its (nonzero) digits is 504000, while the sum is 46.
The spelling of 13118421573055 in words is "thirteen trillion, one hundred eighteen billion, four hundred twenty-one million, five hundred seventy-three thousand, fifty-five".
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