Base | Representation |
---|---|
bin | 10011000101110010001… |
… | …000111111010010011001 |
3 | 11122102012011122011221222 |
4 | 103011302020333102121 |
5 | 132443212233444111 |
6 | 2442400324541425 |
7 | 163531415610146 |
oct | 23056210772231 |
9 | 4572164564858 |
10 | 1311879984281 |
11 | 466402061219 |
12 | 192301b51875 |
13 | 9692c42ab39 |
14 | 476d12853cd |
15 | 241d1d8a7db |
hex | 1317223f499 |
1311879984281 has 2 divisors, whose sum is σ = 1311879984282. Its totient is φ = 1311879984280.
The previous prime is 1311879984257. The next prime is 1311879984287. The reversal of 1311879984281 is 1824899781131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1244248780681 + 67631203600 = 1115459^2 + 260060^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311879984281 - 218 = 1311879722137 is a prime.
It is a super-2 number, since 2×13118799842812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1311879984287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655939992140 + 655939992141.
It is an arithmetic number, because the mean of its divisors is an integer number (655939992141).
Almost surely, 21311879984281 is an apocalyptic number.
It is an amenable number.
1311879984281 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311879984281 is an equidigital number, since it uses as much as digits as its factorization.
1311879984281 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6967296, while the sum is 62.
The spelling of 1311879984281 in words is "one trillion, three hundred eleven billion, eight hundred seventy-nine million, nine hundred eighty-four thousand, two hundred eighty-one".
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