Base | Representation |
---|---|
bin | 1011111011101011100000… |
… | …1001101111000000100010 |
3 | 1201110020210202112112121021 |
4 | 2332322320021233000202 |
5 | 3204424043414302240 |
6 | 43523112523320054 |
7 | 2522611561153312 |
oct | 276727011570042 |
9 | 51406722475537 |
10 | 13119919681570 |
11 | 41a9143696449 |
12 | 157a88a68002a |
13 | 742284330490 |
14 | 335016821442 |
15 | 17b42c57454a |
hex | beeb826f022 |
13119919681570 has 16 divisors (see below), whose sum is σ = 25432459690680. Its totient is φ = 4844278036224.
The previous prime is 13119919681559. The next prime is 13119919681571. The reversal of 13119919681570 is 7518691991131.
13119919681570 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 4 ways, for example, as 7827679244401 + 5292240437169 = 2797799^2 + 2300487^2 .
It is a junction number, because it is equal to n+sod(n) for n = 13119919681499 and 13119919681508.
It is not an unprimeable number, because it can be changed into a prime (13119919681571) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 50461229415 + ... + 50461229674.
Almost surely, 213119919681570 is an apocalyptic number.
13119919681570 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13119919681570 is a deficient number, since it is larger than the sum of its proper divisors (12312540009110).
13119919681570 is a wasteful number, since it uses less digits than its factorization.
13119919681570 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 100922459109.
The product of its (nonzero) digits is 3674160, while the sum is 61.
The spelling of 13119919681570 in words is "thirteen trillion, one hundred nineteen billion, nine hundred nineteen million, six hundred eighty-one thousand, five hundred seventy".
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