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131200000031102 = 265600000015551
BaseRepresentation
bin11101110101001101100001…
…011001010111100101111110
3122012112121010120202222102012
4131311031201121113211332
5114144040100001443402
61143012240431131222
736430613210524262
oct3565154131274576
9565477116688365
10131200000031102
1138893675705722
121286b532673b12
135829150b810a2
1424581846d40a2
151027c2e28d452
hex77536165797e

131200000031102 has 4 divisors (see below), whose sum is σ = 196800000046656. Its totient is φ = 65600000015550.

The previous prime is 131200000031081. The next prime is 131200000031117. The reversal of 131200000031102 is 201130000002131.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×1312000000311023 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32800000007774 + ... + 32800000007777.

It is an arithmetic number, because the mean of its divisors is an integer number (49200000011664).

Almost surely, 2131200000031102 is an apocalyptic number.

131200000031102 is a deficient number, since it is larger than the sum of its proper divisors (65600000015554).

131200000031102 is an equidigital number, since it uses as much as digits as its factorization.

131200000031102 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65600000015553.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 131200000031102 its reverse (201130000002131), we get a palindrome (332330000033233).

The spelling of 131200000031102 in words is "one hundred thirty-one trillion, two hundred billion, thirty-one thousand, one hundred two".

Divisors: 1 2 65600000015551 131200000031102