Base | Representation |
---|---|
bin | 10011000101111001010… |
… | …011001100011110101011 |
3 | 11122102111112122201010012 |
4 | 103011321103030132223 |
5 | 132443434011202032 |
6 | 2442420255242135 |
7 | 163534404563423 |
oct | 23057123143653 |
9 | 4572445581105 |
10 | 1312000100267 |
11 | 46646394212a |
12 | 19233621934b |
13 | 9694b29579c |
14 | 477031d1483 |
15 | 241dc6b56b2 |
hex | 131794cc7ab |
1312000100267 has 2 divisors, whose sum is σ = 1312000100268. Its totient is φ = 1312000100266.
The previous prime is 1312000100263. The next prime is 1312000100371. The reversal of 1312000100267 is 7620010002131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1312000100267 - 22 = 1312000100263 is a prime.
It is not a weakly prime, because it can be changed into another prime (1312000100263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656000050133 + 656000050134.
It is an arithmetic number, because the mean of its divisors is an integer number (656000050134).
Almost surely, 21312000100267 is an apocalyptic number.
1312000100267 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312000100267 is an equidigital number, since it uses as much as digits as its factorization.
1312000100267 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 1312000100267 its reverse (7620010002131), we get a palindrome (8932010102398).
The spelling of 1312000100267 in words is "one trillion, three hundred twelve billion, one hundred thousand, two hundred sixty-seven".
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