Base | Representation |
---|---|
bin | 10011000101111001010… |
… | …011001100111101001011 |
3 | 11122102111112122210210111 |
4 | 103011321103030331023 |
5 | 132443434011232334 |
6 | 2442420255255151 |
7 | 163534404602212 |
oct | 23057123147513 |
9 | 4572445583714 |
10 | 1312000102219 |
11 | 466463943644 |
12 | 19233621a4b7 |
13 | 9694b296641 |
14 | 477031d2079 |
15 | 241dc6b6064 |
hex | 131794ccf4b |
1312000102219 has 2 divisors, whose sum is σ = 1312000102220. Its totient is φ = 1312000102218.
The previous prime is 1312000102199. The next prime is 1312000102223. The reversal of 1312000102219 is 9122010002131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1312000102219 - 25 = 1312000102187 is a prime.
It is a super-2 number, since 2×13120001022192 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1312000102219.
It is not a weakly prime, because it can be changed into another prime (1312000102229) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656000051109 + 656000051110.
It is an arithmetic number, because the mean of its divisors is an integer number (656000051110).
Almost surely, 21312000102219 is an apocalyptic number.
1312000102219 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312000102219 is an equidigital number, since it uses as much as digits as its factorization.
1312000102219 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 22.
The spelling of 1312000102219 in words is "one trillion, three hundred twelve billion, one hundred two thousand, two hundred nineteen".
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