13120021111130 has 16 divisors (see below), whose sum is σ = 23616858320640. Its totient is φ = 5247826150992.

The previous prime is 13120021111111. The next prime is 13120021111151. The reversal of 13120021111130 is 3111112002131.

It is a junction number, because it is equal to n+sod(n) for n = 13120021111099 and 13120021111108.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 22484210 + ... + 23060349.

It is an arithmetic number, because the mean of its divisors is an integer number (1476053645040).

Almost surely, 2^{13120021111130} is an apocalyptic number.

13120021111130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13120021111130 is a deficient number, since it is larger than the sum of its proper divisors (10496837209510).

13120021111130 is a wasteful number, since it uses less digits than its factorization.

13120021111130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45573373.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 13120021111130 its reverse (3111112002131), we get a palindrome (16231133113261).

The spelling of 13120021111130 in words is "thirteen trillion, one hundred twenty billion, twenty-one million, one hundred eleven thousand, one hundred thirty".