Base | Representation |
---|---|
bin | 11000011100000001… |
… | …11100110101011001 |
3 | 1020212100122200112102 |
4 | 30032000330311121 |
5 | 203332212011324 |
6 | 10005515453145 |
7 | 643061301263 |
oct | 141600746531 |
9 | 36770580472 |
10 | 13120032089 |
11 | 5622a0932a |
12 | 2661a571b5 |
13 | 131120a3c8 |
14 | 8c6692b33 |
15 | 51bc61dae |
hex | 30e03cd59 |
13120032089 has 2 divisors, whose sum is σ = 13120032090. Its totient is φ = 13120032088.
The previous prime is 13120032083. The next prime is 13120032097. The reversal of 13120032089 is 98023002131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7294526464 + 5825505625 = 85408^2 + 76325^2 .
It is an emirp because it is prime and its reverse (98023002131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13120032089 - 216 = 13119966553 is a prime.
It is not a weakly prime, because it can be changed into another prime (13120032083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560016044 + 6560016045.
It is an arithmetic number, because the mean of its divisors is an integer number (6560016045).
Almost surely, 213120032089 is an apocalyptic number.
It is an amenable number.
13120032089 is a deficient number, since it is larger than the sum of its proper divisors (1).
13120032089 is an equidigital number, since it uses as much as digits as its factorization.
13120032089 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 29.
The spelling of 13120032089 in words is "thirteen billion, one hundred twenty million, thirty-two thousand, eighty-nine".
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